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16x^2-+2x^2+3x-86=0
We add all the numbers together, and all the variables
18x^2+3x=0
a = 18; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·18·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*18}=\frac{-6}{36} =-1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*18}=\frac{0}{36} =0 $
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